优化目标：28行399步

体积速度都满足，见：https://github.com/atesgoral/hrm-solutions/blob/master/solutions/40-Prime-Factory-28.399/28.247-jdashton.asm

snippet.asm

-- HUMAN RESOURCE MACHINE PROGRAM --
 
a:
b:
    INBOX   
    COPYTO   10
    COPYFROM 24
    COPYTO   22
    BUMPUP   22
    COPYTO   1
c:
    BUMPUP   1
d:
    COPYFROM 24
    COPYTO   12
    SUB      10
e:
    COPYTO   11
    BUMPUP   12
    COPYFROM 11
    ADD      1
    JUMPN    e
    JUMPZ    f
    BUMPDN   22
    JUMPZ    c
    COPYFROM 10
    OUTBOX  
    JUMP     b
f:
    COPYFROM 1
    OUTBOX  
    BUMPDN   12
    JUMPZ    a
    BUMPUP   12
    COPYTO   10
    JUMP     d

提前准备前几个质数

snippet.asm

COPYFROM 24
COPYTO   11
BUMPUP   11
BUMPUP   11
COPYTO   12
BUMPUP   12
ADD      11
COPYTO   13
ADD      11
COPYTO   14
ADD      12
COPYTO   15
BUMPUP   15
ADD      11
COPYTO   16
ADD      12
COPYTO   17
BUMPUP   17
ADD      11
COPYTO   18
 
JUMP     start
 
out:
COPYFROM 23
OUTBOX
 
start:
COPYFROM 24
COPYTO   10
BUMPUP   10
 
INBOX
COPYTO   23
SUB      11
JUMPZ    out
ADD      11
SUB      12
JUMPZ    out
ADD      12
SUB      13
JUMPZ    out
ADD      13
SUB      14
JUMPZ    out
ADD      14
SUB      15
JUMPZ    out
ADD      15
SUB      16
JUMPZ    out
ADD      16
SUB      17
JUMPZ    out
ADD      17
SUB      18
JUMPZ    out
 
continue:
BUMPUP   10
 
prepare:
COPYFROM 24
COPYTO   0
COPYFROM 23
 
test:
SUB      10
JUMPN    continue
JUMPZ    out2
COPYTO   22
BUMPUP   0
COPYFROM 22
JUMP     test
 
out2:
COPYFROM 10
OUTBOX
COPYFROM 0
JUMPZ    start
COPYTO   23
BUMPUP   23
JUMP     prepare

参考：https://github.com/atesgoral/hrm-solutions/blob/master/solutions/40-Prime-Factory-28.399/23.414-fbastien.asm

相对于 439 步，将 test 中 COPYTO 22 移到了JUMPZ，JUMPN 指令之后，并交换了 JUMPZ , JUMPN顺序

snippet.asm

start:
COPYFROM 24
COPYTO   10
BUMPUP   10
 
INBOX
COPYTO   23
 
continue:
BUMPUP   10
 
prepare:
COPYFROM 24
COPYTO   0
COPYFROM 23
 
test:
SUB      10
JUMPN    continue
JUMPZ    out2
COPYTO   22
BUMPUP   0
COPYFROM 22
JUMP     test
 
out2:
COPYFROM 10
OUTBOX
COPYFROM 0
JUMPZ    start
COPYTO   23
BUMPUP   23
JUMP     prepare

snippet.asm

start:
COPYFROM 24
COPYTO   10
BUMPUP   10
 
INBOX
COPYTO   23
 
continue:
BUMPUP   10
 
prepare:
COPYFROM 24
COPYTO   0
COPYFROM 23
 
test:
SUB      10
COPYTO   22
JUMPZ    out2
JUMPN    continue
BUMPUP   0
COPYFROM 22
JUMP     test
 
out2:
COPYFROM 10
OUTBOX
COPYFROM 0
JUMPZ    start
COPYTO   23
BUMPUP   23
JUMP     prepare

snippet.asm

start:
COPYFROM 24
COPYTO   0
COPYTO   10
BUMPUP   10
 
INBOX
COPYTO   23
 
continue:
BUMPDN   23
JUMPZ    start
BUMPUP   10
COPYFROM 24
COPYTO   0
BUMPUP   23
 
test:
SUB      10
COPYTO   22
JUMPZ    out2
JUMPN    continue
BUMPUP   0
COPYFROM 22
JUMP     test
 
out2:
COPYFROM 10
OUTBOX
BUMPUP   0
COPYTO   23
COPYFROM 24
COPYTO   0
COPYFROM 23
JUMP     test

从2开始循环找出因子

snippet.asm

start:
COPYFROM 24
COPYTO   0
COPYTO   10
BUMPUP   10
BUMPUP   10
 
INBOX
COPYTO   23
 
test:
SUB      10
COPYTO   22
JUMPZ    out2
JUMPN    continue
BUMPUP   0
COPYFROM 22
JUMP     test
 
out2:
COPYFROM 10
OUTBOX
BUMPUP   0
COPYTO   23
COPYFROM 24
COPYTO   0
COPYFROM 23
JUMP     test
 
continue:
BUMPUP   10
COPYFROM 24
COPYTO   0
BUMPDN   23
JUMPZ    start
BUMPUP   23
JUMP     test