优化目标：39行109步

见： https://github.com/atesgoral/hrm-solutions/blob/master/solutions/36-Alphabetizer-39.109/27.64-18111398.asm

• 首先将第一个词读入
• 巧妙的利用INBOX中的0初始化22号格子
• 然后依次读入第二个词的字符，和第一个词对应位置比较，直接输出较小的
• 通过22号减23号（23号为第一个词的长度）判断长度，只有 22号-23号 为负的情况下（即第二个词较短），才有必要继续循环下去，如果不为负，说明第一个字符串已经结束了，那么程序也应该结束了。

流程图

snippet.asm

first:
INBOX
COPYTO   [23]
JUMPZ    second
BUMPUP   23
JUMP     first
 
second:
COPYTO   22
 
input:
INBOX
JUMPZ    end
COPYTO   20
SUB      [22]
JUMPZ    out2
JUMPN    output2
 
output1:
COPYFROM [22]
JUMPZ    end
OUTBOX
BUMPUP   22
JUMP     output1
 
output2:
COPYFROM 20
 
o2:
OUTBOX
INBOX
JUMPZ    end
JUMP     o2
 
out2:
COPYFROM 20
OUTBOX
BUMPUP   22
SUB      23
JUMPN    input
 
end:

snippet.asm

COPYFROM 23
COPYTO   20
COPYTO   21
 
first:
INBOX
JUMPZ    second
COPYTO   [23]
BUMPUP   23
JUMP     first
 
second:
COPYTO   [23]
 
input:
INBOX
JUMPZ    replace0
COPYTO   19
COPYFROM [20]
JUMPZ    out
SUB      19
JUMPN    out
COPYFROM 19
SUB      [20]
JUMPN    replace
BUMPUP   20
JUMP     input
 
replace:
COPYFROM 19
COPYTO   [20]
 
continue:
BUMPUP   20
INBOX
JUMPZ    out2
COPYTO   [20]
JUMP     continue
 
 
replace0:
COPYTO   [20]
JUMP     out
 
out2:
COPYTO   [20]
 
out:
COPYFROM [21]
JUMPZ    end
OUTBOX
BUMPUP   21
JUMP     out
 
end:

snippet.asm

COPYFROM 23
COPYTO   20
COPYTO   21
COPYFROM 24
COPYTO   22
 
first:
INBOX
JUMPZ  second
COPYTO [23]
BUMPUP 23
JUMP   first
 
second:
INBOX
JUMPZ  compare
COPYTO [24]
BUMPUP 24
JUMP   second
 
compare:
COPYFROM [22]
SUB      [21]
JUMPN    o2
COPYFROM [21]
SUB      [22]
JUMPN    o1
BUMPUP   20
BUMPUP   21
SUB      23
JUMPZ    o1
BUMPUP   22
SUB      24
JUMPZ    o2
JUMP     compare
 
o1:
COPYFROM 21
SUB      20
COPYTO   21
o11:
SUB      23
JUMPZ    end
COPYFROM [21]
OUTBOX
BUMPUP   21
JUMP     o11
 
o2:
COPYFROM 22
SUB      20
COPYTO   22
o22:
SUB      24
JUMPZ    end
COPYFROM [22]
OUTBOX
BUMPUP   22
JUMP     o22
 
end: