优化目标：14行76步

见：https://github.com/atesgoral/hrm-solutions/blob/master/solutions/39-Re-Coordinator-14.76/35.44-Otto42.asm

见：https://github.com/atesgoral/hrm-solutions/blob/master/solutions/39-Re-Coordinator-14.76/14.73-FireGoblin.asm

跟15行79步类似，15行的问题是 COPYFROM 11 执行了两次，为了省去最后一步的 COPYFROM 14 COPYTO 1，导致 INBOX取的数先存后取，且还是在循环内取，因此多执行了几步。

snippet.asm

JUMP     next
 
out:
ADD      15
OUTBOX
COPYFROM  1
OUTBOX
 
next: 
COPYFROM 14
COPYTO   1
INBOX
 
cal:
SUB      15
JUMPN    out
COPYTO   0
BUMPUP   1
COPYFROM 0
JUMP     cal

snippet.asm

JUMP     next
 
out:
ADD      15
OUTBOX
COPYFROM  1
OUTBOX
 
next: 
INBOX
COPYTO   11
COPYFROM 14
COPYTO   1
 
cal:
COPYFROM 11
SUB      15
JUMPN    out
COPYTO   11
BUMPUP   1
JUMP     cal

snippet.asm

COPYFROM 15
ADD      15
COPYTO   11
ADD      15
COPYTO   7
 
JUMP     next
 
out:
OUTBOX
 
next:
COPYFROM 14
COPYTO   0
INBOX
SUB      15
JUMPN    y0
ADD      15
SUB      11
JUMPN    y1
ADD      11
SUB      7
JUMPN    y2
OUTBOX
BUMPUP   0
BUMPUP   0
BUMPUP   0
JUMP     out
 
y0:
ADD      15
OUTBOX
COPYFROM 0
JUMP     out
 
y1:
ADD      11
SUB      15
OUTBOX
BUMPUP   0
JUMP     out
 
y2:
ADD      7
SUB      11
OUTBOX
BUMPUP   0
BUMPUP   0
JUMP     out

snippet.asm

next:
COPYFROM 14
COPYTO   1
 
INBOX
COPYTO   11
 
cal:
COPYFROM 11
SUB      15
JUMPN    x
COPYTO   11
BUMPUP   1
JUMP     cal
 
x:
ADD      15
 
OUTBOX
COPYFROM  1
OUTBOX
JUMP     next